mlsanityData to 14 Oct 2026

Does a robot path have clearance c?

arXiv 1807.09392 ↗First posted 24 Jul 2018cs.CGcited by 1

Not on the map. Why?

Abstract (arXiv)

Most path planning problems among polygonal obstacles ask to find a path that avoids the obstacles and is optimal with respect to some measure or a combination of measures, for example an u-to-v shortest path of clearance at least c, where u and v are points in the free space and c is a positive constant. In practical applications, such as emergency interventions/evacuations and medical treatment planning, a number of u-to-v paths are suggested by experts and the question is whether such paths satisfy specific requirements, such as a given clearance from the obstacles. We address the following path query problem: Given a set S of m disjoint simple polygons in the plane, with a total of n vertices, preprocess them so that for a query consisting of a positive constant c and a simple polygonal path π with k vertices, from a point u to a point v in free space, where k is much smaller than n, one can quickly decide whether π has clearance at least c (that is, there is no polygonal obstacle within distance c of π). To do so, we show how to solve the following related problem: Given a set S of m simple polygons in Re2, preprocess S into a data structure so that the polygon in S closest to a query line segment s can be reported quickly. We present an O(t log n) time, O(t) space preprocessing, O((n / √t) log 7/2 n) query time solution for this problem, for any n 1 + ε ≤ t ≤ n2. For a path with k segments, this results in O((n k / √t) log 7/2 n) query time, which is a significant improvement over algorithms that can be derived from existing computational geometry methods when k is small.

Key facts. Cited by 1 paper in the map (data through 14 Oct 2026). First posted on arXiv 24 Jul 2018.

Builds on

No reference list yet.

Built on by

Cited by year

Citing papers per year: 2025: 1.

1 paper.